(-3x^3y^3)(-4y^4x^2)(x^2)^-4=2/3y^4

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Solution for (-3x^3y^3)(-4y^4x^2)(x^2)^-4=2/3y^4 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

-4*(-3)*(x^2)^-4*x^2*x^3*y^3*y^4 = (2/3)*y^4 // - (2/3)*y^4

-4*(-3)*(x^2)^-4*x^2*x^3*y^3*y^4-((2/3)*y^4) = 0

(-2/3)*y^4-4*(-3)*(x^2)^-4*x^2*x^3*y^3*y^4 = 0

12*x^-3*y^7 = -(-2/3*y^4) // : 12*y^7

x^-3 = 1/18*y^-3

-3 < 0

1/(x^3) = 1/18*y^-3 // * x^3

1 = 1/18*x^3*y^-3 // : 1/18*y^-3

18*y^3 = x^3

x^3 = 18*y^3 // ^ 1/3

x = 18^(1/3)*y

x = 18^(1/3)*y

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